2a^2-26a-50=0

Solution for 2a^2-26a-50=0 equation:

2a^2-26a-50=0

a = 2; b = -26; c = -50;
Δ = b2-4ac
Δ = -262-4·2·(-50)
Δ = 1076
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1076}=\sqrt{4*269}=\sqrt{4}*\sqrt{269}=2\sqrt{269}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{269}}{2*2}=\frac{26-2\sqrt{269}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{269}}{2*2}=\frac{26+2\sqrt{269}}{4}
$